0=-16t^2+37t+260

Solution for 0=-16t^2+37t+260 equation:

0=-16t^2+37t+260

We move all terms to the left:

0-(-16t^2+37t+260)=0

We add all the numbers together, and all the variables

-(-16t^2+37t+260)=0

We get rid of parentheses

16t^2-37t-260=0

a = 16; b = -37; c = -260;
Δ = b2-4ac
Δ = -372-4·16·(-260)
Δ = 18009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{18009}=\sqrt{9*2001}=\sqrt{9}*\sqrt{2001}=3\sqrt{2001}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-3\sqrt{2001}}{2*16}=\frac{37-3\sqrt{2001}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+3\sqrt{2001}}{2*16}=\frac{37+3\sqrt{2001}}{32}
$